4d N = 1 $$ \mathcal{N}=1 $$ from 6d (1, 0)
Crossref DOI link: https://doi.org/10.1007/JHEP04(2017)064
Published Online: 2017-04-11
Published Print: 2017-04
Update policy: https://doi.org/10.1007/springer_crossmark_policy
Razamat, Shlomo S.
Vafa, Cumrun
Zafrir, Gabi