4d N = 1 $$ \mathcal{N}=1 $$ from 6d N = 1 0 $$ \mathcal{N}=\left(1,0\right) $$ on a torus with fluxes
Crossref DOI link: https://doi.org/10.1007/JHEP06(2017)022
Published Online: 2017-06-05
Published Print: 2017-06
Update policy: https://doi.org/10.1007/springer_crossmark_policy
Bah, Ibrahima
Hanany, Amihay
Maruyoshi, Kazunobu
Razamat, Shlomo S.
Tachikawa, Yuji
Zafrir, Gabi