c − a from the N = 1 $$ \mathcal{N}=1 $$ superconformal index
Crossref DOI link: https://doi.org/10.1007/JHEP12(2014)145
Published Online: 2014-12-22
Published Print: 2014-12
Update policy: https://doi.org/10.1007/springer_crossmark_policy
Ardehali, Arash Arabi
Liu, James T.
Szepietowski, Phillip