On the exponential Diophantine equation $$(3pm^2-1)^x+(p(p-3)m^2+1)^y=(pm)^z$$ ( 3 p m 2 - 1 ) x + ( p ( p - 3 ) m 2 + 1 ) y = ( p m ) z
Crossref DOI link: https://doi.org/10.1007/s10998-016-0162-z
Published Online: 2016-11-07
Published Print: 2017-06
Update policy: https://doi.org/10.1007/springer_crossmark_policy
Terai, Nobuhiro
Hibino, Takeshi
License valid from 2016-11-07