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Solving $x+x^{2^{l}}+\cdots +x^{2^{ml}}=a$ over $\mathbb {F}_{2^{n}}$

Crossref DOI link: https://doi.org/10.1007/s12095-020-00425-3

Published Online: 2020-02-11

Published Print: 2020-07

Update policy: https://doi.org/10.1007/springer_crossmark_policy

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