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The reverse order law $$(ab)^\#=b^\dag (a^\dag abb^\dag )^\dag a^\dag $$ ( a b ) # = b † ( a † a b b † ) † a † in rings with involution

Crossref DOI link: https://doi.org/10.1007/s13398-014-0178-2

Published Online: 2014-07-02

Published Print: 2015-09

Update policy: https://doi.org/10.1007/springer_crossmark_policy